b^2=-2b+15

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Solution for b^2=-2b+15 equation:


Simplifying
b2 = -2b + 15

Reorder the terms:
b2 = 15 + -2b

Solving
b2 = 15 + -2b

Solving for variable 'b'.

Reorder the terms:
-15 + 2b + b2 = 15 + -2b + -15 + 2b

Reorder the terms:
-15 + 2b + b2 = 15 + -15 + -2b + 2b

Combine like terms: 15 + -15 = 0
-15 + 2b + b2 = 0 + -2b + 2b
-15 + 2b + b2 = -2b + 2b

Combine like terms: -2b + 2b = 0
-15 + 2b + b2 = 0

Factor a trinomial.
(-5 + -1b)(3 + -1b) = 0

Subproblem 1

Set the factor '(-5 + -1b)' equal to zero and attempt to solve: Simplifying -5 + -1b = 0 Solving -5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1b = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1b = 0 + 5 -1b = 0 + 5 Combine like terms: 0 + 5 = 5 -1b = 5 Divide each side by '-1'. b = -5 Simplifying b = -5

Subproblem 2

Set the factor '(3 + -1b)' equal to zero and attempt to solve: Simplifying 3 + -1b = 0 Solving 3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1b = 0 + -3 -1b = 0 + -3 Combine like terms: 0 + -3 = -3 -1b = -3 Divide each side by '-1'. b = 3 Simplifying b = 3

Solution

b = {-5, 3}

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